Parallel Circuit Problems Episode 904 Answer Key

By | May 28, 2023

Parallel Circuit Problems Episode 904 Answer Key

Problem 1

In the circuit shown below, what is the total current flowing through the circuit?  10 Ω / \ / \ +--+-----------+--+ +--+ | | | | | | 12 V 10 Ω 10 Ω 10 Ω | | | | | | \ / +--+ 

Solution:

The total current flowing through the circuit is 2 A. To solve this problem, we can use the following formula:  I = \frac{V}{R}  where: *

I

is the current in amps *

V

is the voltage in volts *

R

is the resistance in ohms In this problem, we have: *

= 12 V *

R

= 10 Ω + 10 Ω + 10 Ω = 30 Ω So, the total current flowing through the circuit is:  I = \frac{12 V}{30 Ω} = 2 A 

Problem 2

What is the voltage drop across each resistor in the circuit shown in problem 1?

Solution:

The voltage drop across each resistor is 4 V. To solve this problem, we can use the following formula:  V = IR  where: *

V

is the voltage in volts *

I

is the current in amps *

R

is the resistance in ohms In this problem, we have: *

= 4 V *

= 2 A *

R

= 10 Ω So, the voltage drop across each resistor is:  V = IR = 2 A * 10 Ω = 4 V 

Problem 3

What is the power dissipated by each resistor in the circuit shown in problem 1?

Solution:

The power dissipated by each resistor is 8 W. To solve this problem, we can use the following formula:  P = IV  where: *

P

is the power in watts *

I

is the current in amps *

V

is the voltage in volts In this problem, we have: *

= 8 W *

= 2 A *

V

= 4 V So, the power dissipated by each resistor is:  P = IV = 2 A * 4 V = 8 W 

Problem 4

If the resistance of each resistor in the circuit shown in problem 1 is increased by 20%, what will be the total current flowing through the circuit?

Solution:

The total current flowing through the circuit will decrease by 10%. To solve this problem, we can use the following formula:  I = \frac{V}{R}  where: *

I

is the current in amps *

V

is the voltage in volts *

R

is the resistance in ohms In this problem, we have: *

= 12 V *

R

= 10 Ω + 10 Ω + 10 Ω = 30 Ω So, the total current flowing through the circuit is:  I = \frac{12 V}{30 Ω} = 2 A  If the resistance of each resistor is increased by 20%, the total resistance of the circuit will increase to:  R = 30 Ω * 1.2 = 36 Ω  So, the total current flowing through the circuit will decrease to:  I = \frac{12 V}{36 Ω} = \frac{2}{3} A = 0.67 A  Therefore, the total current flowing through the circuit will decrease by 10%.

Problem 5

If the voltage in the circuit shown in problem 1 is increased by 20%, what will be the voltage drop across each resistor?

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