## Draw the Logic Circuit for Boolean Expression X Y XZ

The logic circuit for the Boolean expression X Y XZ can be drawn as follows: The circuit consists of three inputs, X, Y, and Z, and one output, F. The inputs are connected to the inputs of three AND gates, and the outputs of the AND gates are connected to the inputs of an OR gate. The output of the OR gate is the final output of the circuit. The Boolean expression X Y XZ can be simplified as follows: ``` X Y XZ = (X Y) Z + X (Y Z) ``` This means that the circuit can be simplified to the following: The simplified circuit consists of two AND gates and one OR gate. The inputs to the AND gates are X Y and X (Y Z), respectively. The output of the AND gates are connected to the inputs of the OR gate. The output of the OR gate is the final output of the circuit. The following table shows the truth table for the Boolean expression X Y XZ: | X | Y | Z | F | |---|---|---|---| | 0 | 0 | 0 | 0 | | 0 | 0 | 1 | 0 | | 0 | 1 | 0 | 0 | | 0 | 1 | 1 | 1 | | 1 | 0 | 0 | 0 | | 1 | 0 | 1 | 1 | | 1 | 1 | 0 | 1 | | 1 | 1 | 1 | 1 | The logic circuit for the Boolean expression X Y XZ can be used to implement a variety of logic functions, such as AND, OR, and XOR. It can also be used to implement more complex logic functions, such as multiplexers and demultiplexers.Boolean Algebra And Logic Gates

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